Give the main product of the following reactions:
$(i)$ $1, 2-$dibromopropane + alcoholic $KOH$
$(ii)$ $1, 1, 2, 2-$tetrabromoethane + zinc powder in methanol
$(i)$ $1, 2-$dibromopropane + alcoholic $KOH$
$(ii)$ $1, 1, 2, 2-$tetrabromoethane + zinc powder in methanol
(N/A) $(i)$ The reaction of $1, 2-$dibromopropane with alcoholic $KOH$ undergoes dehydrohalogenation to form propene:
$CH_3CHBrCH_2Br + 2KOH \xrightarrow{\text{alcoholic}} CH_3CH=CH_2 + 2KBr + 2H_2O$
$(ii)$ The reaction of $1, 1, 2, 2-$tetrabromoethane with zinc powder in methanol undergoes debromination to form ethyne:
$CHBr_2-CHBr_2 + 2Zn \xrightarrow{CH_3OH, \Delta} CH \equiv CH + 2ZnBr_2$
$CH_3CHBrCH_2Br + 2KOH \xrightarrow{\text{alcoholic}} CH_3CH=CH_2 + 2KBr + 2H_2O$
$(ii)$ The reaction of $1, 1, 2, 2-$tetrabromoethane with zinc powder in methanol undergoes debromination to form ethyne:
$CHBr_2-CHBr_2 + 2Zn \xrightarrow{CH_3OH, \Delta} CH \equiv CH + 2ZnBr_2$
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$1,4-\text{cyclohexadiene-1,4-dicarboxylic acid}$ $\xrightarrow{NaOH} A$ $\xrightarrow{\text{Kolbe electrolysis}} B$
In the following reactions,the product $S$ is
Which of the following reactions are not feasible?
$I$. $CH_3CH=CH_2 \xrightarrow{HCl, (C_6H_5CO)_2O_2} CH_3CH_2CH_2Cl$
$II$. $C_6H_6 + CH_3CH_2CH_2Cl \xrightarrow{AlCl_3} C_6H_5CH(CH_3)_2$
$III$. $CH_3CHClCH_2Cl \xrightarrow{KOH, \Delta} CH_3C \equiv CH$
$IV$. $CH_3CH=CHCH_3 \xrightarrow{KMnO_4 / H^+} CH_3COOH$
$I$. $CH_3CH=CH_2 \xrightarrow{HCl, (C_6H_5CO)_2O_2} CH_3CH_2CH_2Cl$
$II$. $C_6H_6 + CH_3CH_2CH_2Cl \xrightarrow{AlCl_3} C_6H_5CH(CH_3)_2$
$III$. $CH_3CHClCH_2Cl \xrightarrow{KOH, \Delta} CH_3C \equiv CH$
$IV$. $CH_3CH=CHCH_3 \xrightarrow{KMnO_4 / H^+} CH_3COOH$
DifficultAP EAMCET 2023
View SolutionStyrene on reaction with reagent $X$ gave $Y$, which on hydrolysis followed by oxidation gave $Z$. $Z$ gives a positive $2,4-DNP$ test but does not give the iodoform test. What are $X$ and $Z$ respectively?
Consider the following reactions:
$(a)$ $CH_3-CH=CH_2 + HBr \rightarrow CH_3-CH(Br)-CH_3$
$(b)$ $CH_3-CH=CH_2 + HBr \xrightarrow{Peroxide} CH_3-CH_2-CH_2Br$
$(c)$ $CH_4 + Cl_2 \xrightarrow{hv} CH_3Cl + HCl$
Which of these reactions proceed via a free radical mechanism?
$(a)$ $CH_3-CH=CH_2 + HBr \rightarrow CH_3-CH(Br)-CH_3$
$(b)$ $CH_3-CH=CH_2 + HBr \xrightarrow{Peroxide} CH_3-CH_2-CH_2Br$
$(c)$ $CH_4 + Cl_2 \xrightarrow{hv} CH_3Cl + HCl$
Which of these reactions proceed via a free radical mechanism?
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