What are the advantages of the $CHN$ elemental analysis method?

$6.46 \ g$ of $BaSO_4$ is obtained from $4.81 \ g$ of a compound in the estimation of sulphur by the Carius method. Calculate the percentage of sulphur in the compound. (Atomic masses: $Ba = 137, S = 32, O = 16$)

An organic compound is subjected to chlorination to get compound $A$. When $0.5 \ g$ of compound $A$ is reacted with $AgNO_3$ [Carius Method],it forms $0.3849 \ g$ of $AgCl$. Calculate the percentage of chlorine in compound $A$. (Round off to the nearest integer)
(Atomic masses of $Ag$ and $Cl$ are $107.87$ and $35.5$ respectively)

In the estimation of bromine,$0.5 \ g$ of an organic compound gave $0.40 \ g$ of silver bromide. The percentage of bromine in the given compound is $..... \ \%$ (nearest integer).
(Relative atomic masses of $Ag$ and $Br$ are $108 \ u$ and $80 \ u$,respectively).

In the Kjeldahl method,$0.35 \ g$ of an organic compound produces ammonia,which is absorbed in $100 \ mL$ of $0.1 \ M \ H_2SO_4$. The excess $H_2SO_4$ requires $154 \ mL$ of $0.1 \ M \ NaOH$ for titration. Calculate the percentage of nitrogen in the compound. (Given atomic masses: $C=12, H=1, O=16, N=14, S=32$)

For the estimation of nitrogen,$1.4 \ g$ of an organic compound was digested by Kjeldahl method and the evolved ammonia was absorbed in $60 \ mL$ of $\frac{M}{10}$ sulphuric acid. The unreacted acid required $20 \ mL$ of $\frac{M}{10}$ sodium hydroxide for complete neutralization. The percentage of nitrogen in the compound is .....$\%$