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(C) The property of matrices states that $A \cdot (	ext{adj } A) = |A| I$,where $I$ is the identity matrix of order $3 	imes 3$.First,we calculate t

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$\begin{bmatrix} 68 & 0 & 0 \ 0 & 68 & 0 \ 0 & 0 & 68 \end{bmatrix}$

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(C) The property of matrices states that $A \cdot (	ext{adj } A) = |A| I$,where $I$ is the identity matrix of order $3 	imes 3$.First,we calculate the determinant of matrix $A$:$|A| = x(yz - 8) - 3(z - 8) + 2(2 - 2y)$$|A| = xyz - 8x - 3z + 24 + 4 - 4y$$|A| = xyz - (8x + 4y + 3z) + 28$Substituting the given values $xyz = 60$ and $8x + 4y + 3z = 20$:$|A| = 60 - 20 + 28 = 68$Therefore,$A \cdot (	ext{adj } A) = 68 I = \begin{bmatrix} 68 & 0 & 0 \ 0 & 68 & 0 \ 0 & 0 & 68 \end{bmatrix}$.

Given $A = \begin{bmatrix} x & 3 & 2 \\ 1 & y & 4 \\ 2 & 2 & z \end{bmatrix}$,$xyz = 60$ and $8x + 4y + 3z = 20$,then $A \cdot (\text{adj } A)$ is equal to

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