If $A = \left[\begin{array}{cc}1+2 i & i \\ -i & 1-2 i\end{array}\right]$ where $i=\sqrt{-1}$,then $A (\operatorname{adj} A )=\ldots$. (in $I$)

If $A$ and $B$ are invertible matrices,which one of the following statements is not correct?

Suppose $n > 1$ and $A$ is a non-singular matrix of order $n$ such that $|\operatorname{adj} A| = |\operatorname{adj}(\operatorname{adj} A)|$. Then the matrix whose rank is $n$ is:

Find the inverse,by elementary row operations (if possible),of the following matrix: $\left[\begin{array}{cc}1 & 3 \\ -5 & 7\end{array}\right]$

If $AB = \begin{bmatrix} -6 & 26 \\ -1 & 19 \end{bmatrix}$ and $11B^{-1} = \begin{bmatrix} 5 & -3 \\ 2 & 1 \end{bmatrix}$,then $A = $ . . . . . . .

Let $A$ be a matrix of order $3 \times 3$ and $\det(A) = 2$. Then $\det(\det(A) \cdot \operatorname{adj}(5 \operatorname{adj}(A^3)))$ is equal to: