Given $5$ different green toys,$4$ different blue toys,and $3$ different red toys,how many combinations of toys can be chosen taking at least one green and one blue toy?

  • A
    $32 \times 16 \times 4$
  • B
    $31 \times 15 \times 4$
  • C
    $32 \times 16 \times 8$
  • D
    $31 \times 15 \times 8$

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