Given below are two statements :
Statement $I$: $[Ni(CN)_4]^{2-}$ is square planar and diamagnetic complex with $dsp^2$ hybridization for $Ni$ but $[Ni(CO)_4]$ is tetrahedral,diamagnetic and with $sp^3$ hybridization for $Ni$.
Statement $II$: $[NiCl_4]^{2-}$ and $[Ni(CO)_4]$ both have same $d$-electron configuration,have same geometry and are paramagnetic.
In light of the above statements,choose the correct answer from the options given below:

  • A
    Both Statement $I$ and Statement $II$ are true.
  • B
    Both Statement $I$ and Statement $II$ are false.
  • C
    Statement $I$ is correct but statement $II$ is false.
  • D
    Statement $I$ is incorrect but statement $II$ is true.

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Similar Questions

The pair$(s)$ of complexes wherein both exhibit tetrahedral geometry is(are):
Note: $py = \text{pyridine}$
Given: Atomic numbers of $Fe, Co, Ni$ and $Cu$ are $26, 27, 28$ and $29$,respectively.
$(A)$ $[FeCl_4]^-$ and $[Fe(CO)_4]^{2-}$
$(B)$ $[Co(CO)_4]^-$ and $[CoCl_4]^{2-}$
$(C)$ $[Ni(CO)_4]$ and $[Ni(CN)_4]^{2-}$
$(D)$ $[Cu(py)_4]^+$ and $[Cu(CN)_4]^{3-}$

Triple degenerate $d-$ orbitals are exactly half-filled in

Define the following term: Coordination polyhedron.

Identify the number of unpaired electrons present and the geometry of the $[Co(NH_3)_6]^{3+}$ complex, respectively.

Match the following:
List-$I$ (Hybridisation)List-$II$ (Compound/ion)
$A. sp^3d$$I. [PtCl_4]^{2-}$
$B. sp^3d^2$$II. SF_6$
$C. dsp^2$$III. BCl_3$
$D. dsp^3$$IV. PCl_5$
$V. ClF_3$

The correct match is:

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