Given below are two statements: one is labell | vedclass

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(B) The Ellingham diagram plots $\Delta G^{\circ}$ versus $T$. The slope of the line is $-\Delta S$. At the melting point of the metal $(Mg)$,the meta

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Both $A$ and $R$ are true and $R$ is the correct explanation of $A$.

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(B) The Ellingham diagram plots $\Delta G^{\circ}$ versus $T$. The slope of the line is $-\Delta S$. At the melting point of the metal $(Mg)$,the metal changes from solid to liquid state $(Mg_{(s)} \rightarrow Mg_{(l)})$. This phase change involves a significant change in entropy $(\Delta S)$. Since the entropy of the liquid state is higher than that of the solid state,the value of $\Delta S$ for the reaction $2Mg_{(l)} + O_2(g) \rightarrow 2MgO_{(s)}$ becomes more negative than for $2Mg_{(s)} + O_2(g) \rightarrow 2MgO_{(s)}$. Consequently,the slope $(-\Delta S)$ increases sharply at the melting point $(\sim 1120^{\circ} C)$. Thus,both Assertion $A$ and Reason $R$ are true,and $R$ is the correct explanation of $A$.

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