Given below are two statements:Statement I: P | vedclass

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(C) Hybridisation analysis:$PF_5$: The central atom $P$ has $5$ bond pairs and $0$ lone pairs,resulting in $sp^3 d$ hybridisation.$BrF_5$: The central

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Both Statement $I$ and Statement $II$ are false

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(C) Hybridisation analysis:$PF_5$: The central atom $P$ has $5$ bond pairs and $0$ lone pairs,resulting in $sp^3 d$ hybridisation.$BrF_5$: The central atom $Br$ has $5$ bond pairs and $1$ lone pair,resulting in $sp^3 d^2$ hybridisation.$SF_6$: The central atom $S$ has $6$ bond pairs and $0$ lone pairs,resulting in $sp^3 d^2$ hybridisation.$[Co(NH_3)_6]^{3+}$: The central metal ion $Co^{3+}$ ($d^6$ configuration) with a strong field ligand $NH_3$ undergoes inner orbital hybridisation,resulting in $d^2 sp^3$ hybridisation.Conclusion:Statement $I$ is false because $BrF_5$ is $sp^3 d^2$.Statement $II$ is false because $[Co(NH_3)_6]^{3+}$ is $d^2 sp^3$.Therefore,both statements are false.

Given below are two statements:
Statement $I$: $PF_5$ and $BrF_5$ both exhibit $sp^3 d$ hybridisation.
Statement $II$: Both $SF_6$ and $[Co(NH_3)_6]^{3+}$ exhibit $sp^3 d^2$ hybridisation.
In the light of the above statements,choose the correct answer from the options given below:

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Given below are two statements:Statement $I$: $PF_5$ and $BrF_5$ both exhibit $sp^3 d$ hybridisation.Statement $II$: Both $SF_6$ and $[Co(NH_3)_6]^{3+}$ exhibit $sp^3 d^2$ hybridisation.In the light of the above statements,choose the correct answer from the options given below: