Given below are two statements:
Statement $I$: Due to increase in van der Waals forces, the order of boiling points is $CH_3CH_2CH_2I > CH_3CH_2I > CH_3I$.
Statement $II$: As $para$-dichlorobenzene is more symmetric, its melting point is higher than $ortho$-dichlorobenzene, however its boiling point is lower than $ortho$-dichlorobenzene.
In the light of the above statements, choose the correct answer from the options given below:

  • A
    Both Statement $I$ and Statement $II$ are true
  • B
    Both Statement $I$ and Statement $II$ are false
  • C
    Statement $I$ is true but Statement $II$ is false
  • D
    Statement $I$ is false but Statement $II$ is true

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Which of the following is not formed in the given reaction?
$C_6H_5CH_2Cl + CH_3Cl \xrightarrow{Na, \text{dry ether}}$

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Assertion : Alkylbenzene is not prepared by Friedel-Crafts alkylation of benzene.
Reason : Alkyl halides are less reactive than acyl halides.

Choose the correct option:
$A$. $ROH + SOCl_2 \rightarrow$ $P$. Darzen process
$B$. $RX (Cl, Br) + NaI \rightarrow$ $Q$. Finkelstein reaction
$C$. $RX (Cl, Br) + AgF \rightarrow$ $R$. Swarts reaction
$D$. $ArX + RX + Na \rightarrow$ $S$. Wurtz-Fittig reaction

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