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(B) To find the frictional force applied by the wall on block $B$,we consider the system of both blocks $A$ and $B$ in equilibrium.Since the system is

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$120$

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(B) To find the frictional force applied by the wall on block $B$,we consider the system of both blocks $A$ and $B$ in equilibrium.Since the system is in equilibrium,the total downward gravitational force must be balanced by the upward frictional force exerted by the wall on block $B$.The total weight of the system is $W_{total} = W_A + W_B = 20\ N + 100\ N = 120\ N$.Let $f_{wall}$ be the frictional force exerted by the wall on block $B$.For the system to be in vertical equilibrium,the upward force must equal the downward force:$f_{wall} = W_{total} = 120\ N$.Thus,the frictional force applied by the wall on block $B$ is $120\ N$.

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