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(D) We use the relation $\Delta G^o = -nFE^o$.For reaction $(i): Fe^{2+} + 2e^- 	o Fe$,$\Delta G_1^o = -2 	imes F 	imes (-0.440 \ V) = 0.880 \ F$.F

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$+0.771$

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(D) We use the relation $\Delta G^o = -nFE^o$.For reaction $(i): Fe^{2+} + 2e^- 	o Fe$,$\Delta G_1^o = -2 	imes F 	imes (-0.440 \ V) = 0.880 \ F$.For reaction $(ii): Fe^{3+} + 3e^- 	o Fe$,$\Delta G_2^o = -3 	imes F 	imes (-0.036 \ V) = 0.108 \ F$.We want the reaction: $Fe^{3+} + e^- 	o Fe^{2+}$.This can be obtained by $(ii) - (i)$:$\Delta G_3^o = \Delta G_2^o - \Delta G_1^o = 0.108 \ F - 0.880 \ F = -0.772 \ F$.Since $\Delta G_3^o = -nFE^o$ where $n=1$:$-0.772 \ F = -1 	imes F 	imes E^o$.$E^o = +0.772 \ V \approx +0.771 \ V$.

Given standard electrode potentials:
$Fe^{2+} + 2e^- \to Fe; E^o = -0.440 \ V$
$Fe^{3+} + 3e^- \to Fe; E^o = -0.036 \ V$
The standard electrode potential $(E^o)$ for $Fe^{3+} + e^- \to Fe^{2+}$ is .............. $V$.

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Given standard electrode potentials:$Fe^{2+} + 2e^- \to Fe; E^o = -0.440 \ V$$Fe^{3+} + 3e^- \to Fe; E^o = -0.036 \ V$The standard electrode potential $(E^o)$ for $Fe^{3+} + e^- \to Fe^{2+}$ is .............. $V$.