Glucose or sucrose are soluble in water but cyclohexane or benzene (simple six-membered ring compounds) are insoluble in water. Explain.

(N/A) glucose molecule contains five $-OH$ groups,while a sucrose molecule contains eight $-OH$ groups. These $-OH$ groups allow glucose and sucrose to form extensive hydrogen bonds with water molecules,making them soluble. In contrast,cyclohexane and benzene are non-polar hydrocarbons that do not contain $-OH$ groups. Consequently,they cannot form hydrogen bonds with water,rendering them insoluble in water.