Hemant decided to build a farmhouse in 40 day | vedclass

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(A) Let the total work be completed by $100$ men in $x$ days.Work done by $100$ men in $35$ days + work done by $200$ men in $5$ days = $1$ (total wor

Vedclass · Accepted Answer

$5$

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(A) Let the total work be completed by $100$ men in $x$ days.Work done by $100$ men in $35$ days + work done by $200$ men in $5$ days = $1$ (total work).Using the formula $\frac{M_1 D_1}{W_1} = \frac{M_2 D_2}{W_2}$:$\frac{100 	imes 35}{W} + \frac{200 	imes 5}{W} = 1$,where $W$ is the total work in man-days.$W = (100 	imes 35) + (200 	imes 5) = 3500 + 1000 = 4500$ man-days.If only $100$ men were employed,the time taken would be $\frac{4500}{100} = 45$ days.The stipulated time was $40$ days.Therefore,the delay would be $45 - 40 = 5$ days.

Hemant decided to build a farmhouse in $40$ days. He employed $100$ men in the beginning and $100$ more after $35$ days and completed the construction in the stipulated time. If he had not employed the additional men,how many days behind schedule would it have been finished? (in days)

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