How can the magnetic field of a solenoid be i | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The magnetic field of a solenoid is given by the formula $B = \mu_0 n I$, where $n$ is the number of turns per unit length and $I$ is the electric

Vedclass · Accepted Answer

Both $(A)$ and $(B)$.

Vedclass · Answer

(C) The magnetic field of a solenoid is given by the formula $B = \mu_0 n I$, where $n$ is the number of turns per unit length and $I$ is the electric current.$1$. If we increase the number of turns per unit length $(n)$, the magnetic field increases.$2$. If a ferromagnetic material (core) like soft iron is placed inside the solenoid, the magnetic field increases many times due to its relative permeability $(\mu_r)$ $(B = \mu_0 \mu_r n I)$.Therefore, the correct option is $(C)$.

How can the magnetic field of a solenoid be increased for a given current?

Similar Questions

Ampere's circuital law is associated with which law?

$A$ $50 \ cm$ long solenoid has a winding of $400$ turns. What current must pass through it to produce a magnetic field of induction $4 \pi \times 10^{-3} \ T$ at the centre (in $A$)?

Write the equation for the magnetic field at an inside point of a very long solenoid.

$A$ direct current $I$ flows along the length of an infinitely long straight thin-walled pipe. Then the magnetic field is

$A$ solenoid of length $0.5 \ m$ has a radius of $1 \ cm$ and is made up of $250$ turns. It carries a current of $5 \ A$. What is the magnitude of the magnetic field inside the solenoid?

Vedclass Test Series

Exam Paper Generator

Online Exam Module