How does the gravitational force (F) between | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) According to the universal law of gravitation,the gravitational force $(F)$ acting between two objects is inversely proportional to the square of

Vedclass · Accepted Answer

$F'=4F$

Vedclass · Answer

(D) According to the universal law of gravitation,the gravitational force $(F)$ acting between two objects is inversely proportional to the square of the distance $(r)$ between them,i.e.,$F = G \frac{m_{1} m_{2}}{r^{2}}$If the distance $r$ is reduced to $r/2$,the new gravitational force $(F')$ will be:$F' = G \frac{m_{1} m_{2}}{(r/2)^{2}}$$F' = G \frac{m_{1} m_{2}}{r^{2}/4}$$F' = 4 	imes (G \frac{m_{1} m_{2}}{r^{2}})$$F' = 4F$Therefore,if the distance is reduced to half,the gravitational force becomes four times the original value.

How does the gravitational force $(F)$ between two objects change when the distance between them is reduced to half?

Similar Questions

$A$ ball is thrown vertically upwards with a velocity of $49\, m/s$. Calculate
$(i)$ the maximum height to which it rises,
$(ii)$ the total time it takes to return to the surface of the earth.

Gravitational force acts on all objects in proportion to their masses. Why then,a heavy object does not fall faster than a light object?

What do you mean by free fall?

State the universal law of gravitation.

$A$ stone is released from the top of a tower of height $19.6\, m$. Calculate its final velocity just before touching the ground. (in $, ms^{-1}$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module