How is an atom represented? Why?
(N/A) An atom is represented by the notation $^A_Z X$,where $X$ is the chemical symbol of the element,$Z$ is the atomic number (number of protons),and $A$ is the mass number (total number of protons and neutrons).
The positive charge in the nucleus is due to the protons. $A$ proton carries one unit of fundamental charge and is stable.
All the electrons of an atom are outside the nucleus and revolve around it in circular orbits due to the electrostatic Coulomb force.
The number of electrons in a neutral atom is equal to the atomic number $Z$. Hence,the total charge of the electrons is $(-Ze)$.
Since the atom is electrically neutral,the total positive charge of the nucleus must be $(+Ze)$. Therefore,the number of protons in the nucleus is equal to the atomic number $Z$.
The positive charge in the nucleus is due to the protons. $A$ proton carries one unit of fundamental charge and is stable.
All the electrons of an atom are outside the nucleus and revolve around it in circular orbits due to the electrostatic Coulomb force.
The number of electrons in a neutral atom is equal to the atomic number $Z$. Hence,the total charge of the electrons is $(-Ze)$.
Since the atom is electrically neutral,the total positive charge of the nucleus must be $(+Ze)$. Therefore,the number of protons in the nucleus is equal to the atomic number $Z$.
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In the Rutherford's nuclear model of the atom,the nucleus (radius about $10^{-15} \; m$) is analogous to the sun about which the electron moves in an orbit (radius $\approx 10^{-10} \; m$) like the earth orbits around the sun. If the dimensions of the solar system had the same proportions as those of the atom,would the earth be closer to or farther away from the sun than it actually is? The radius of the earth's orbit is about $1.5 \times 10^{11} \; m$. The radius of the sun is taken as $7 \times 10^{8} \; m$.
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View SolutionAccording to classical theory,the circular path of an electron in a Rutherford atom is
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View SolutionAccording to classical theory,the Rutherford atom was:
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View SolutionThe graph which depicts the results of the Rutherford gold foil experiment with $\alpha$-particles is:
$\theta$: Scattering angle
$Y$: Number of scattered $\alpha$-particles detected
(Plots are schematic and not to scale)
$\theta$: Scattering angle
$Y$: Number of scattered $\alpha$-particles detected
(Plots are schematic and not to scale)
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