How is work done by a force measured? A porte | vedclass

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(A) Work done by a force is measured as the product of the magnitude of the force applied and the displacement in the direction of the force $(W = F \

Vedclass · Accepted Answer

Work is the product of force and displacement. The work done is $340 \, J$.

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(A) Work done by a force is measured as the product of the magnitude of the force applied and the displacement in the direction of the force $(W = F 	imes S)$.Given:Mass of the luggage $(m)$ = $20 \, kg$Displacement $(h)$ = $1.7 \, m$Acceleration due to gravity $(g)$ = $10 \, m s^{-2}$The force applied by the porter to lift the luggage is equal to the weight of the luggage,which is $F = m 	imes g$.Therefore,the work done $(W)$ = $m 	imes g 	imes h$.$W = 20 \, kg 	imes 10 \, m s^{-2} 	imes 1.7 \, m$.$W = 340 \, J$.Thus,the work done by the porter on the luggage is $340 \, J$.

Height of object $(m)$	$PE$ $(J)$	$KE$ $(J)$	Mechanical Energy $(J)$
$10$	...	...	...
$8$	...	...	...
$5$	...	...	...
Just above ground	...	...	...

How is work done by a force measured? $A$ porter lifts a luggage of $20 \, kg$ from the ground and puts it on his head $1.7 \, m$ above the ground. Find the work done by the porter on the luggage. $(g = 10 \, m s^{-2})$

Similar Questions

$(a)$ Is it possible that a body is in accelerated motion under the action of a force,yet no work is being done by the force? Explain with an example.
$(b)$ Two bodies of masses $m_{1}$ and $m_{2}$ have equal kinetic energies. What is the ratio of their linear momenta?

When the speed of a moving object is doubled,its:

An object of mass $10 \ kg$ is made to fall freely from a height of $10 \ m$. Complete the table:

Height of object $(m)$ $PE$ $(J)$ $KE$ $(J)$ Mechanical Energy $(J)$

$10$ ... ... ...

$8$ ... ... ...

$5$ ... ... ...

Just above ground ... ... ...

Hence,state the law of conservation of energy.

State the law of conservation of energy.

$(a)$ How much work is done when a force of $1\, N$ moves a body through a distance of $1\, m$ in its direction?
$(b)$ Is it possible that a force is acting on a body but still the work done is zero? Explain giving one example.

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