How many mL of 1 , M H_2SO_4 is required to n | vedclass

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(B) The neutralization reaction is: $H_2SO_4 + 2NaOH \rightarrow Na_2SO_4 + 2H_2O$. According to the law of equivalence,the number of equivalents of a

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$5$

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(B) The neutralization reaction is: $H_2SO_4 + 2NaOH ightarrow Na_2SO_4 + 2H_2O$. According to the law of equivalence,the number of equivalents of acid must equal the number of equivalents of base. $N_1 V_1 = N_2 V_2$. For $H_2SO_4$,normality $N_1 = Molarity 	imes n	ext{-factor} = 1 	imes 2 = 2 \, N$. For $NaOH$,normality $N_2 = Molarity 	imes n	ext{-factor} = 1 	imes 1 = 1 \, N$. Substituting the values: $2 	imes V_1 = 1 	imes 10$. $V_1 = \frac{10}{2} = 5 \, mL$.

How many $mL$ of $1 \, M$ $H_2SO_4$ is required to neutralize $10 \, mL$ of $1 \, M$ $NaOH$ solution?

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