(B) $NH_4NO_3$ consists of $NH_4^{+}$ and $NO_3^{-}$ ions.For the ammonium ion $(NH_4^{+})$: Let the oxidation number of $N$ be $x$. Then $x + 4(+1) =

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(B) $NH_4NO_3$ consists of $NH_4^{+}$ and $NO_3^{-}$ ions.For the ammonium ion $(NH_4^{+})$: Let the oxidation number of $N$ be $x$. Then $x + 4(+1) = +1$,which gives $x = -3$.For the nitrate ion $(NO_3^{-})$: Let the oxidation number of $N$ be $x$. Then $x + 3(-2) = -1$,which gives $x - 6 = -1$,so $x = +5$.Thus,the oxidation numbers of nitrogen are $-3$ and $+5$.

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What are the oxidation numbers of nitrogen in $NH_4NO_3$?

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A
$+3, -5$
B
$-3, +5$
C
$+3, -6$
D
$+2, +2$

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What are the oxidation numbers of nitrogen in $NH_4NO_3$?

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