How many ATP and NADPH molecules are required | vedclass

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(B) For the synthesis of one molecule of glucose $(C_6H_{12}O_6)$ via the Calvin cycle, $6$ turns are required.Each turn fixes one $CO_2$ molecule, co

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$(2)$ $18$ $ATP$ and $12$ $NADPH$

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(B) For the synthesis of one molecule of glucose $(C_6H_{12}O_6)$ via the Calvin cycle, $6$ turns are required.Each turn fixes one $CO_2$ molecule, consuming $3$ $ATP$ and $2$ $NADPH$.Therefore, for $6$ $CO_2$ molecules, the total requirement is:$6 	imes 3 = 18$ $ATP$$6 	imes 2 = 12$ $NADPH$Thus, $18$ $ATP$ and $12$ $NADPH$ molecules are required to produce one molecule of glucose.

How many $ATP$ and $NADPH$ molecules are required to make one molecule of glucose through the Calvin pathway?

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