How many moles of magnesium phosphate,$Mg_{3}(PO_{4})_{2}$ will contain $0.25 \ mol$ of oxygen atoms?
- A$1.25 \times 10^{-2}$
- B$2.5 \times 10^{-2}$
- C$0.02$
- D$3.125 \times 10^{-2}$
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Match List-$I$ with List-$II$. List-$I$ (Mass of substance) List-$II$ (Number of atoms) $A$. $1.8 \text{ mg}$ water $I$. $2 \times 10^{-4} \times N_{A}$ $B$. $9.8 \text{ mg}$ sulphuric acid $II$. $1.5 \times 10^{-4} \times N_{A}$ $C$. $1.8 \text{ mg}$ carbon $III$. $3 \times 10^{-4} \times N_{A}$ $D$. $5.85 \text{ mg}$ salt (NaCl) $IV$. $7 \times 10^{-4} \times N_{A}$
| List-$I$ (Mass of substance) | List-$II$ (Number of atoms) |
| $A$. $1.8 \text{ mg}$ water | $I$. $2 \times 10^{-4} \times N_{A}$ |
| $B$. $9.8 \text{ mg}$ sulphuric acid | $II$. $1.5 \times 10^{-4} \times N_{A}$ |
| $C$. $1.8 \text{ mg}$ carbon | $III$. $3 \times 10^{-4} \times N_{A}$ |
| $D$. $5.85 \text{ mg}$ salt (NaCl) | $IV$. $7 \times 10^{-4} \times N_{A}$ |
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