How many oxygen atoms are present in 0.36 g | vedclass

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Question

(B) The molar mass of water $(H_2O)$ is $18 \ g/mol$. Number of moles of water $= \frac{0.36 \ g}{18 \ g/mol} = 0.02 \ mol$. Number of water molecules

Vedclass · Accepted Answer

$1.205 	imes 10^{22}$

Vedclass · Answer

(B) The molar mass of water $(H_2O)$ is $18 \ g/mol$. Number of moles of water $= \frac{0.36 \ g}{18 \ g/mol} = 0.02 \ mol$. Number of water molecules $= 0.02 	imes 6.023 	imes 10^{23} = 1.205 	imes 10^{22}$ molecules. Since each molecule of water $(H_2O)$ contains $1$ oxygen atom, the number of oxygen atoms is equal to the number of water molecules. Therefore, the number of oxygen atoms $= 1.205 	imes 10^{22}$.

How many oxygen atoms are present in $0.36 \ g$ of a drop of water?

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