How many three-digit numbers can be formed fr | vedclass

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(D) To form a three-digit number divisible by $5$,the unit's place (the third digit) must be $5$.Since the digit $5$ is used in the unit's place and r

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$20$

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(D) To form a three-digit number divisible by $5$,the unit's place (the third digit) must be $5$.Since the digit $5$ is used in the unit's place and repetition is not allowed,we have $5$ remaining digits $(2, 3, 6, 7, 9)$ to fill the remaining two positions.The tens place can be filled by any of the remaining $5$ digits in $5$ ways.The hundreds place can be filled by any of the remaining $4$ digits in $4$ ways.Therefore,the total number of such three-digit numbers is $1 	imes 5 	imes 4 = 20$.

How many three-digit numbers can be formed from the digits $2, 3, 5, 6, 7,$ and $9$ which are divisible by $5$,given that no digit is repeated?

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