How many types of equilibrium are there based on the proportion of reactant and product?

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(N/A) There are $3$ types of equilibrium based on the proportion of reactant and product:
$(i)$ Reactant is negligible and product is maximum: Such reactions proceed towards completion. At equilibrium,the concentration of reactant is negligible. At equilibrium,nearly $100 \%$ product is present,where $K > 10^{3}$.
Example: $H_{2(g)} + \frac{1}{2} O_{2(g)} \xrightarrow{500 \ K} H_{2}O_{(g)}$; $K_{c} = 2.4 \times 10^{47}$.
$(ii)$ Reactant is more and product is less: In such reactions,at equilibrium,most of the reactant remains unreacted. The product concentration is very low. Its equilibrium constant is very small,i.e.,$K < 10^{-3}$. Such reactions hardly proceed in the forward direction.
Example: $H_{2}O_{(g)} \xrightarrow{500 \ K} H_{2(g)} + \frac{1}{2} O_{2(g)}$; $K_{c} = 4.1 \times 10^{-48}$.
$(iii)$ Reactant and products are comparable: In such reactions,both reactant and product are present in significant amounts at equilibrium. In such reactions,$K_{c}$ ranges from $10^{-3}$ to $10^{3}$.
Example: $H_{2(g)} + I_{2(g)} \xrightarrow{700 \ K} 2 HI_{(g)}$; $K_{c} = 57$.

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The equilibrium constant for the reaction $N_{2(g)} + O_{2(g)} \rightleftharpoons 2 NO_{(g)}$ is $4 \times 10^{-4}$ at $2000 \ K$. In the presence of a catalyst, the equilibrium is attained $10$ times faster. Therefore, the equilibrium constant, in the presence of the catalyst at $2000 \ K$ is:

The equilibrium constant for the reaction $N_{2(g)} + O_{2(g)} \rightleftharpoons 2NO_{(g)}$ is $4 \times 10^{-4}$ at $2000 \ K$. In the presence of a catalyst,the equilibrium is attained ten times faster. Therefore,the equilibrium constant in the presence of a catalyst at $2000 \ K$ is:

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