How will you bring about the following conversions in not more than two steps?
$(i)$ Propanone to Propene
$(ii)$ Benzoic acid to Benzaldehyde
$(iii)$ Ethanol to $3-$Hydroxybutanal
$(iv)$ Benzene to $m-$Nitroacetophenone
$(v)$ Benzaldehyde to Benzophenone
$(vi)$ Bromobenzene to $1-$Phenylethanol
$(vii)$ Benzaldehyde to $3-$Phenylpropan$-1-$ol
$(viii)$ Benzaldehyde to $\alpha-$Hydroxyphenylacetic acid
$(ix)$ Benzoic acid to $m-$Nitrobenzyl alcohol

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(D)
$(i)$ $CH_3COCH_3$ $\xrightarrow{NaBH_4} CH_3CH(OH)CH_3$ $\xrightarrow{\text{conc. } H_2SO_4, \Delta} CH_3CH=CH_2$
$(ii)$ $C_6H_5COOH$ $\xrightarrow{SOCl_2} C_6H_5COCl$ $\xrightarrow{H_2/Pd-BaSO_4} C_6H_5CHO$
$(iii)$ $CH_3CH_2OH$ $\xrightarrow{PCC} CH_3CHO$ $\xrightarrow{\text{dil. } NaOH} CH_3CH(OH)CH_2CHO$
$(iv)$ $C_6H_6$ $\xrightarrow{CH_3COCl/AlCl_3} C_6H_5COCH_3$ $\xrightarrow{\text{conc. } HNO_3/H_2SO_4} m-NO_2-C_6H_4COCH_3$
$(v)$ $C_6H_5CHO$ $\xrightarrow[2. H_3O^+]{1. C_6H_5MgBr} C_6H_5CH(OH)C_6H_5$ $\xrightarrow{Na_2Cr_2O_7/H_2SO_4} C_6H_5COC_6H_5$
$(vi)$ $C_6H_5Br$ $\xrightarrow{Mg/\text{ether}} C_6H_5MgBr$ $\xrightarrow[2. H_3O^+]{1. CH_3CHO} C_6H_5CH(OH)CH_3$
$(vii)$ $C_6H_5CHO + CH_3CHO$ $\xrightarrow{\text{dil. } NaOH} C_6H_5CH=CHCHO$ $\xrightarrow{H_2/Ni} C_6H_5CH_2CH_2CH_2OH$
$(viii)$ $C_6H_5CHO$ $\xrightarrow{HCN} C_6H_5CH(OH)CN$ $\xrightarrow{H_3O^+} C_6H_5CH(OH)COOH$
$(ix)$ $C_6H_5COOH$ $\xrightarrow{\text{conc. } HNO_3/H_2SO_4} m-NO_2-C_6H_4COOH$ $\xrightarrow{B_2H_6} m-NO_2-C_6H_4CH_2OH$

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