Hybridisation of the central atom in $NF_3$ is
- A$sp^3$
- B$sp$
- C$sp^2$
- D$dsp^2$
Explore More
Similar Questions
Chlorine atom,in its third excited state,reacts with fluorine to form a compound $X$. The formula and shape of $X$ are :
Give an example and explain the meaning of hybridization.
Medium
View SolutionMatch the species given in Column-$I$ with the hybridizations given in Column-$II$.
Column-$I$ Column-$II$ $A$. Boron in $[B(OH)_4]^-$ $1$. $sp^2$ $B$. Aluminum in $[Al(H_2O)_6]^{3+}$ $2$. $sp^3$ $C$. Boron in $B_2H_6$ $3$. $sp^3d^2$ $D$. Carbon in Buckminsterfullerene $E$. $Si$ in $SiO_4^{4-}$ $F$. $Ge$ in $[GeCl_6]^{2-}$
| Column-$I$ | Column-$II$ |
|---|---|
| $A$. Boron in $[B(OH)_4]^-$ | $1$. $sp^2$ |
| $B$. Aluminum in $[Al(H_2O)_6]^{3+}$ | $2$. $sp^3$ |
| $C$. Boron in $B_2H_6$ | $3$. $sp^3d^2$ |
| $D$. Carbon in Buckminsterfullerene | |
| $E$. $Si$ in $SiO_4^{4-}$ | |
| $F$. $Ge$ in $[GeCl_6]^{2-}$ |
Medium
View SolutionIn which of the following reactions is there no change in the hybridisation of the central atom?
Differentiate between atomic orbitals and hybrid orbitals.
Difficult
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo