$I$ toss three coins together. The possible outcomes are no heads,$1$ head,$2$ heads and $3$ heads. So,$I$ say that probability of no heads is $\frac{1}{4}$. What is wrong with this conclusion?

  • A
    The total number of outcomes is not $4$.
  • B
    The outcomes are not equally likely.
  • C
    The probability of no heads is $\frac{1}{8}$,not $\frac{1}{4}$.
  • D
    Both $A$ and $C$.

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