An iceberg floats in water with part of it su | vedclass

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(B) The density of ice is $ho_{	ext{ice}} = 0.917 \, g/cm^3$.The density of water is $ho_{w} = 1 \, g/cm^3$.Let the total volume of the iceberg b

Vedclass · Accepted Answer

$0.917$

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(B) The density of ice is $ho_{	ext{ice}} = 0.917 \, g/cm^3$.The density of water is $ho_{w} = 1 \, g/cm^3$.Let the total volume of the iceberg be $V$.Let the volume of the iceberg submerged in water be $V^{\prime}$.For a body floating in equilibrium,the weight of the body must be equal to the weight of the liquid displaced by the submerged part of the body (Archimedes' Principle).Weight of iceberg = Weight of water displaced$V \cdot ho_{	ext{ice}} \cdot g = V^{\prime} \cdot ho_{w} \cdot g$Dividing both sides by $V \cdot ho_{w} \cdot g$,we get the fraction of submerged volume:$\frac{V^{\prime}}{V} = \frac{ho_{	ext{ice}}}{ho_{w}} = \frac{0.917}{1} = 0.917$.

An iceberg floats in water with part of it submerged. What is the fraction of the volume of the iceberg submerged if the density of ice is ${\rho _i} = 0.917 \, g/cm^3$?

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