Identify [A],[B],and [C],respectively in the | vedclass

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Question

(C) The given reaction sequence is as follows $:$ $1$. Aniline $(C_6H_5NH_2)$ reacts with $NaNO_2$ and $HCl$ at $273-278 \ K$ to form benzene diazoniu

Vedclass · Accepted Answer

$[A] = 	ext{Aniline}, [B] = 	ext{Iodobenzene}, [C] = 	ext{Biphenyl}$

Vedclass · Answer

(C) The given reaction sequence is as follows $:$ $1$. Aniline $(C_6H_5NH_2)$ reacts with $NaNO_2$ and $HCl$ at $273-278 \ K$ to form benzene diazonium chloride $(C_6H_5N_2^+Cl^-)$. Thus,$[A]$ is aniline. $2$. Benzene diazonium chloride reacts with $KI$ to form iodobenzene $(C_6H_5I)$. Thus,$[B]$ is iodobenzene. $3$. Iodobenzene reacts with $2Na$ in the presence of dry ether (Wurtz-Fittig reaction) to form biphenyl $(C_6H_5-C_6H_5)$. Thus,$[C]$ is biphenyl. Therefore,the correct sequence is $[A] = 	ext{Aniline}, [B] = 	ext{Iodobenzene}, [C] = 	ext{Biphenyl}$.

Identify $[A]$,$[B]$,and $[C]$,respectively in the following reaction sequence $:$

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