Identify $X$ and $Y$ in the following reactions:

  • A
    $X$ = Nitrosobenzene,$Y$ = Hydrazobenzene
  • B
    $X$ = Aniline,$Y$ = Hydrazobenzene
  • C
    $X$ = Phenylhydroxylamine,$Y$ = Hydrazobenzene
  • D
    $X$ = Hydrazobenzene,$Y$ = Phenylhydroxylamine

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Similar Questions

State True or False for the following statements:
$(i)$ Aniline becomes polar in its resonance structure.
$(ii)$ The separation of charge occurs in the resonance structure of aniline.
$(iii)$ The $NH_2$ group of aniline is electron donating.
$(iv)$ The $NH_2$ group of aniline is electron attracting in resonance $(-R)$.

$R-CONH_2 \xrightarrow[\Delta]{KOBr} R-NH_2$. The correct statement about the product is:

The reduction of benzenediazonium chloride to phenylhydrazine can be accomplished by:

Predict the major product of the following reaction sequence:
$CH_3-C(H)(C_6H_4-D)-COCl$ $\xrightarrow{NH_3} \text{Intermediate}$ $\xrightarrow{OH^-/Br_2} \text{Product}$

Aniline reacts with mixed acid (conc. $HNO_3$ and conc. $H_2SO_4$) at $288 \ K$ to give $P$ $(51 \%)$,$Q$ $(47 \%)$ and $R$ $(2 \%)$. The major product$(s)$ of the following reaction sequence is (are):
$R$ $\xrightarrow[2) Br_2, CH_3CO_2H]{1) Ac_2O, \text{pyridine}}$ $\xrightarrow{3) H_3O^+}$ $\xrightarrow{4) NaNO_2, HCl / 273-278 \ K}$ $\xrightarrow{5) EtOH, \Delta}$ $\xrightarrow{6) Sn/HCl}$ $\xrightarrow{7) Br_2/H_2O \text{ (excess)}} \text{Major Product}$

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