Identify X and Y in the following reactions:X | vedclass

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(B) $1$. For the reaction $X \xrightarrow{H_2/Ni} CH_3CH_2CH_2NH_2$,the reduction of a nitrile $(R-CN)$ with $H_2/Ni$ adds four hydrogen atoms to prod

Vedclass · Accepted Answer

$CH_3CH_2CN \quad CH_3CH_2CH_2CONH_2$

Vedclass · Answer

(B) $1$. For the reaction $X \xrightarrow{H_2/Ni} CH_3CH_2CH_2NH_2$,the reduction of a nitrile $(R-CN)$ with $H_2/Ni$ adds four hydrogen atoms to produce a primary amine $(R-CH_2NH_2)$. To obtain $CH_3CH_2CH_2NH_2$ (propan$-1-$amine),$X$ must be $CH_3CH_2CN$ (propanenitrile).$2$. For the reaction $Y \xrightarrow{Br_2/NaOH} CH_3CH_2CH_2NH_2$,this is the Hofmann bromamide degradation reaction,which converts an amide $(R-CONH_2)$ into a primary amine $(R-NH_2)$ with one less carbon atom. To obtain $CH_3CH_2CH_2NH_2$ (propan$-1-$amine),$Y$ must be $CH_3CH_2CH_2CONH_2$ (butanamide).$3$. Therefore,$X = CH_3CH_2CN$ and $Y = CH_3CH_2CH_2CONH_2$.

Identify $X$ and $Y$ in the following reactions:
$X \xrightarrow{H_2/Ni} CH_3CH_2CH_2NH_2 \xleftarrow{Br_2/NaOH} Y$

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Identify $X$ and $Y$ in the following reactions:$X \xrightarrow{H_2/Ni} CH_3CH_2CH_2NH_2 \xleftarrow{Br_2/NaOH} Y$