Identify the final product in the following reaction:
$CH_3-CH(OH)-COOH \xrightarrow{\Delta} \text{Product}$

  • A
    Option A
  • B
    $CH_2=CHCO_2H$
  • C
    $CH_3-CO-COOH$
  • D
    $CH_3CH_2OH$

Explore More

Similar Questions

Considering the reaction sequence given below,the correct statement$(s)$ is(are):
$A$. $P$ can be reduced to a primary alcohol using $NaBH_4$.
$B$. Treating $P$ with conc. $NH_4OH$ solution followed by acidification gives $Q$.
$C$. Treating $Q$ with a solution of $NaNO_2$ in aq. $HCl$ liberates $N_2$.
$D$. $P$ is more acidic than $CH_3CH_2COOH$.

Identify $Z$ in the following reaction sequence:
$CH_3COONH_4$ $\xrightarrow{\Delta} X$ $\xrightarrow{P_2O_5} Y$ $\xrightarrow{H_2O/H^+} Z$

Match the reactions given in Column-$I$ with their products in Column-$II$.
Column-$I$ (Reactant) Column-$II$ (Product)
$A$. $RCH_2OH \xrightarrow[(ii) H_3O^{+}]{(i) NaOH, KMnO_4} ?$ $i$. $C_6H_5COOH + C_2H_5OH$
$B$. $CH_3(CH_2)_8CH_2OH \xrightarrow{Jones reagent} ?$ $ii$. $RCOOH$
$C$. $RCONH_2 \xrightarrow{H_3O^{+}, \Delta} ?$ $iii$. $CH_3(CH_2)_8COOH$
$D$. $C_6H_5COOEt \xrightarrow{H_3O^{+}} ?$ $iv$. $RCOOH + NH_3$

Difficult
View Solution

An unknown compound $(A)$ (molar mass $= 180$) on acylation gives a product (molar mass $= 390$). Find the number of hydroxyl group present in compound $(A)$.

Product $(G)$ is

Difficult
View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo