Identify from the following the correct set o | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The spontaneity of a reaction is determined by the Gibbs free energy equation: $\Delta G = \Delta H - T\Delta S$. For a reaction to be non-spontan

Vedclass · Accepted Answer

$\Delta H > 0$ and $\Delta S < 0$

Vedclass · Answer

(D) The spontaneity of a reaction is determined by the Gibbs free energy equation: $\Delta G = \Delta H - T\Delta S$. For a reaction to be non-spontaneous,$\Delta G$ must be greater than $0$ $(\Delta G > 0)$. If $\Delta H > 0$ (endothermic) and $\Delta S Since $T$ is always positive in Kelvin,$\Delta G$ will always be positive regardless of the temperature. Therefore,the reaction is non-spontaneous at all temperatures when $\Delta H > 0$ and $\Delta S < 0$.

Identify from the following the correct set of thermodynamic conditions for the reaction to be non-spontaneous at all temperatures.

Similar Questions

$2 \, mol$ of zinc is dissolved in $HCl$ at $25 \, ^oC$. What is the work done in an open vessel?

Which of the following relations is correct?

The temperature in $K$ at which $\Delta G = 0$, for a given reaction with $\Delta H = -20.5 \ kJ \ mol^{-1}$ and $\Delta S = -50.0 \ J \ K^{-1} \ mol^{-1}$ is:

The reaction $MgO_{(s)} + C_{(s)} \to Mg_{(s)} + CO_{(g)}$,for which $\Delta_r H^o = +491.1 \ kJ \ mol^{-1}$ and $\Delta_r S^o = 198.0 \ J \ K^{-1} \ mol^{-1}$,is not feasible at $298 \ K$. The temperature above which the reaction will be feasible is ..... $K$.

Spontaneity of a chemical reaction is decided by the negative change in

Vedclass Test Series

Exam Paper Generator

Online Exam Module