Identify,from the following,the diamagnetic,t | vedclass

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(D) In $[Ni(Cl)_4]^{2-}$,$Ni$ exists as $Ni^{2+}$ ion $(3d^8)$. Since $Cl^-$ is a weak field ligand,it does not cause pairing of electrons. Thus,it is

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$[Ni(CO)_4]$

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(D) In $[Ni(Cl)_4]^{2-}$,$Ni$ exists as $Ni^{2+}$ ion $(3d^8)$. Since $Cl^-$ is a weak field ligand,it does not cause pairing of electrons. Thus,it is paramagnetic and tetrahedral with $sp^3$ hybridization.$(B)$ In $[Co(C_2O_4)_3]^{3-}$,$(C_2O_4)^{2-}$ is a bidentate ligand,resulting in an octahedral structure.$(C)$ In $[Ni(CN)_4]^{2-}$,$Ni$ exists as $Ni^{2+}$ ion $(3d^8)$. Since $CN^-$ is a strong field ligand,it causes pairing of electrons in the $3d$ orbital. Thus,it is diamagnetic and square planar with $dsp^2$ hybridization.$(D)$ In $[Ni(CO)_4]$,$Ni$ has an oxidation state of $0$ $(3d^8 4s^2)$. $CO$ is a strong field ligand that causes the pairing of electrons,promoting the $4s$ electrons into the $3d$ orbital. The complex is tetrahedral with $sp^3$ hybridization and is diamagnetic.Therefore,$(D)$ is the correct answer.

Column $I$	Column $II$
$(A)$ $sp^3$	$(i)$ $[Co(NH_3)_6]^{3+}$
$(B)$ $dsp^2$	$(ii)$ $[Ni(CO)_4]$
$(C)$ $sp^3d^2$	$(iii)$ $[Pt(NH_3)_2Cl_2]$
$(D)$ $d^2sp^3$	$(iv)$ $[CoF_6]^{3-}$
	$(v)$ $[Fe(CO)_5]$

Identify,from the following,the diamagnetic,tetrahedral complex.

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