Identify product $B$ in the following reaction: $Aniline$ $\xrightarrow{NaNO_2 + HCl, 273 \ K} A$ $\xrightarrow{H_2O, \Delta} B + N_2 \uparrow$

  • A
    Chlorobenzene
  • B
    Benzyl alcohol
  • C
    Benzenediazonium chloride
  • D
    Phenol

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The correct order of basicity of the various nitrogen atoms in $LSD$ is:

What is the major alkene formed in the following Hofmann elimination?

Which statements are True? $A$. In Hoffmann bromamide degradation, $4$ moles of $NaOH$ and $1$ mole of $Br_{2}$ are consumed per mole of an amide. $B$. Hoffmann bromamide reaction is not given by alkyl amides. $C$. Primary amines can be synthesized by Hoffmann bromamide degradation. $D$. Secondary amide on reaction with $Br_{2}$ and $NaOH$ will give secondary amine. $E$. The by-products of Hoffmann degradation are $Na_{2}CO_{3}$, $NaBr$ and $H_{2}O$. Choose the correct answer from the options given below:

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Reason : Acetylation increases the electron density in the benzene ring.

The major product in the following reaction is:

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