(C) We know that $H = E + PV$. For an ideal gas,$PV = nRT$. Therefore,$H = E + nRT$. For two different states at constant temperature $T$: $H_1 = E_1

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

$H_2 - H_1 - E_2 + E_1 = n_2RT - n_1RT$

(C) We know that $H = E + PV$. For an ideal gas,$PV = nRT$. Therefore,$H = E + nRT$. For two different states at constant temperature $T$: $H_1 = E_1 + n_1RT$ and $H_2 = E_2 + n_2RT$. Subtracting the first equation from the second: $(H_2 - H_1) = (E_2 - E_1) + (n_2RT - n_1RT)$. Rearranging this gives: $H_2 - H_1 - E_2 + E_1 = n_2RT - n_1RT$.

Class 11 Chemistry Thermodynamics Basic concepts

Easy

Identify the correct equation relating enthalpy $(H)$ and internal energy $(E)$.

MHT CET 2010 All MHT CET

A
$E_2 - E_1 - H_2 + H_1 = n_2RT - n_1RT$
B
$E_2 - E_1 - H_2 - H_1 = n_2RT - n_1RT$
C
$H_2 - H_1 - E_2 + E_1 = n_2RT - n_1RT$
D
$H_2 - H_1 - E_2 + E_1 = n_2RT + n_1RT$

Explore More

Browse All

Question Bank

All Subjects

Class 11 Questions

Class 11

Chemistry Questions

Chapter

Thermodynamics

Subtopic

Basic concepts

Previous Year

MHT CET 2010 Paper All MHT CET years →

Explain mechanical work.

Medium

View Solution

$A$ gas expands from a volume of $1 \ m^{3}$ to a volume of $2 \ m^{3}$ against an external pressure of $10^{5} \ Nm^{-2}$. The work done by the gas will be

MediumKCET 2012

View Solution

Fill in the blanks:
$(i)$ During the ........... process,there is no absorption or evolution of heat.
$(ii)$ The equation $\Delta G = \Delta H - T\Delta S$ was proposed by ........... .

Medium

View Solution

Heat exchanged in a chemical reaction at constant temperature and constant pressure is called as

Easy

View Solution

Enthalpy change for freezing of $1 \ g$ of water at $1 \ bar$ and $0^{\circ} C$ is $334 \ J$. Calculate the internal energy change in $J$ when $1 \ g$ of water is converted into ice?

MediumTS EAMCET 2019

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

Identify the correct equation relating enthalpy $(H)$ and internal energy $(E)$.

Similar Questions

Explain mechanical work.

$A$ gas expands from a volume of $1 \ m^{3}$ to a volume of $2 \ m^{3}$ against an external pressure of $10^{5} \ Nm^{-2}$. The work done by the gas will be

Fill in the blanks:$(i)$ During the ........... process,there is no absorption or evolution of heat.$(ii)$ The equation $\Delta G = \Delta H - T\Delta S$ was proposed by ........... .

Heat exchanged in a chemical reaction at constant temperature and constant pressure is called as

Enthalpy change for freezing of $1 \ g$ of water at $1 \ bar$ and $0^{\circ} C$ is $334 \ J$. Calculate the internal energy change in $J$ when $1 \ g$ of water is converted into ice?

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Fill in the blanks:
$(i)$ During the ........... process,there is no absorption or evolution of heat.
$(ii)$ The equation $\Delta G = \Delta H - T\Delta S$ was proposed by ........... .