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(C) Let us analyze each molecule: $1$. $PCl_5$: The central atom $P$ has $5$ bond pairs and $0$ lone pairs. Hybridisation is $sp^3d$ and the shape is

Vedclass · Accepted Answer

MoleculeHybridisationShape$SF_6$$sp^3d^2$octahedral

Vedclass · Answer

(C) Let us analyze each molecule: $1$. $PCl_5$: The central atom $P$ has $5$ bond pairs and $0$ lone pairs. Hybridisation is $sp^3d$ and the shape is trigonal bipyramidal. $2$. $[Ni(CN)_4]^{2-}$: $Ni^{2+}$ has $d^8$ configuration. $CN^-$ is a strong field ligand,causing pairing of electrons. Hybridisation is $dsp^2$ and the shape is square planar. $3$. $SF_6$: The central atom $S$ has $6$ bond pairs and $0$ lone pairs. Hybridisation is $sp^3d^2$ and the shape is octahedral. This is the correct set. $4$. $IF_3$: The central atom $I$ has $3$ bond pairs and $2$ lone pairs. Hybridisation is $sp^3d$ and the shape is bent $T$-shaped.

List-$I$	List-$II$
$P.$ $[Cr(NH_3)_4Cl_2]Cl$	$1.$ Paramagnetic and exhibits ionisation isomerism
$Q.$ $[Ti(H_2O)_5Cl](NO_3)_2$	$2.$ Diamagnetic and exhibits cis-trans isomerism
$R.$ $[Pt(en)(NH_3)_2Cl_2]NO_3$	$3.$ Paramagnetic and exhibits cis-trans isomerism
$S.$ $[Co(NH_3)_4(NO_3)_2]NO_3$	$4.$ Diamagnetic and exhibits ionisation isomerism
Codes: $P, Q, R, S$

List-$I$	List-$II$
$A$. Ziegler-Natta	$i$. $Fe_4[Fe(CN)_6]_3$
$B$. Brown ring complex	$ii$. $[Fe(H_2O)_5NO]SO_4$
$C$. Prussian Blue	$iii$. $Al(C_2H_5)_3 + TiCl_4$
$D$. Turnbull Blue	$iv$. $Fe_3[Fe(CN)_6]_2$

Identify the correct set from the following table:

Similar Questions

The given complex $M(ABCDEF)$ exhibits which of the following isomerism?

Match List-$I$ with List-$II$ and select the correct code:

List-$I$ List-$II$

$A$. Ziegler-Natta $i$. $Fe_4[Fe(CN)_6]_3$

$B$. Brown ring complex $ii$. $[Fe(H_2O)_5NO]SO_4$

$C$. Prussian Blue $iii$. $Al(C_2H_5)_3 + TiCl_4$

$D$. Turnbull Blue $iv$. $Fe_3[Fe(CN)_6]_2$

Correct code is:

The number of species having a square planar shape from the following is $........$.
$XeF_4$,$SF_4$,$SiF_4$,$BF_4^{-}$,$BrF_4^{-}$,$[Cu(NH_3)_4]^{2+}$,$[FeCl_4]^{2-}$,$[PtCl_4]^{2-}$

The complexes given below show:

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