Identify the correct statement among the foll | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) When the temperature of a metal is increased,the atoms in it start to vibrate more rigorously. This leads to an increase in the number of collisio

Vedclass · Accepted Answer

Resistivity of metals increases with temperature because number of collisions between electrons increases.

Vedclass · Answer

(C) When the temperature of a metal is increased,the atoms in it start to vibrate more rigorously. This leads to an increase in the number of collisions between the electrons and the lattice ions. Thus,the average time between successive collisions,known as the relaxation time ' $	au$ ',decreases. The resistivity ' $ho$ ' of a metal is given by the formula: $ho = \frac{m}{n e^2 	au}$. Here,$m$ is the mass of an electron,$n$ is the number density of free electrons,and $e$ is the charge of an electron. Since $ho \propto \frac{1}{	au}$,as the relaxation time ' $	au$ ' decreases with increasing temperature,the resistivity ' $ho$ ' increases.

Identify the correct statement among the following.

Similar Questions

$A$ metal wire of $1 \text{ cm}$ length and $1 \text{ mm}$ radius has a resistance of $3 \times 10^{-3} \Omega$. If a wire of the same metal of length $3 \text{ cm}$ and radius $0.5 \text{ mm}$ is drawn,what is the resistance of the new wire (in $\Omega$)?

The resistance of a wire is $R$. It is bent at the middle by $180^o$ and both the ends are twisted together to make a shorter wire. The resistance of the new wire is

$A$ wire has a resistance of $3.1 \Omega$ at $30^{\circ} C$ and $4.5 \Omega$ at $100^{\circ} C$. The temperature coefficient of resistance of the wire is

The resistance of a resistance wire is $5\,\Omega$ at $50\,^{\circ}\text{C}$ and $6\,\Omega$ at $100\,^{\circ}\text{C}$. The resistance at $0\,^{\circ}\text{C}$ will be ............. $\Omega$.

The temperature coefficient of resistance at $0\,^{\circ}\text{C}$ is $\alpha = 0.00125\,^{\circ}\text{C}^{-1}$. At a temperature of $25\,^{\circ}\text{C}$,the resistance of a conductor is $1\,\Omega$. Find the temperature at which the resistance becomes $1.2\,\Omega$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module