Identify the elements X and Y using the ionis | vedclass

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(A) For element $X$,the jump from $IE_1$ $(495 \ kJ/mol)$ to $IE_2$ $(4563 \ kJ/mol)$ is very large,indicating that the second electron is removed fro

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$X=Na, Y=Mg$

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(A) For element $X$,the jump from $IE_1$ $(495 \ kJ/mol)$ to $IE_2$ $(4563 \ kJ/mol)$ is very large,indicating that the second electron is removed from a stable noble gas core. This corresponds to $Na$ $([Ne] 3s^1)$.For element $Y$,the values $IE_1$ $(731 \ kJ/mol)$ and $IE_2$ $(1450 \ kJ/mol)$ are relatively close,which is characteristic of an alkaline earth metal like $Mg$ $([Ne] 3s^2)$,where both valence electrons are removed easily compared to the third electron.Therefore,$X=Na$ and $Y=Mg$.

Element	Ionization energy $1^{st}$ $(kJ/mol)$	Ionization energy $2^{nd}$ $(kJ/mol)$
$X$	$495$	$4563$
$Y$	$731$	$1450$

Identify the elements $X$ and $Y$ using the ionisation energy values given below :

Element Ionization energy $1^{st}$ $(kJ/mol)$ Ionization energy $2^{nd}$ $(kJ/mol)$

$X$ $495$ $4563$

$Y$ $731$ $1450$

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Identify the elements $X$ and $Y$ using the ionisation energy values given below : Element Ionization energy $1^{st}$ $(kJ/mol)$ Ionization energy $2^{nd}$ $(kJ/mol)$ $X$ $495$ $4563$ $Y$ $731$ $1450$