Identify the formula of text{Bis(ethylenediam | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) $1$. The central metal ion is $	ext{Platinum}$ in oxidation state $+IV$, denoted as $Pt^{4+}$.$2$. $	ext{Bis(ethylenediamine)}$ indicates two $e

Vedclass · Accepted Answer

$[Pt(en)_2(SCN)_2]^{2+}$

Vedclass · Answer

(C) $1$. The central metal ion is $	ext{Platinum}$ in oxidation state $+IV$, denoted as $Pt^{4+}$.$2$. $	ext{Bis(ethylenediamine)}$ indicates two $en$ ligands, which are neutral ($0$ charge).$3$. $	ext{Dithiocyanato}$ indicates two $SCN^-$ ligands, each with a $-1$ charge.$4$. The total charge on the complex ion is calculated as: $	ext{Charge} = 	ext{Oxidation state of } Pt + (2 	imes 	ext{charge of } en) + (2 	imes 	ext{charge of } SCN^-)$.$5$. $	ext{Charge} = (+4) + (2 	imes 0) + (2 	imes -1) = +4 - 2 = +2$.$6$. Thus, the formula is $[Pt(en)_2(SCN)_2]^{2+}$.

Identify the formula of $\text{Bis(ethylenediamine)dithiocyanatoplatinum(IV) ion}$ from the following.

Similar Questions

The correct formula of diammine dichlorodicyano chromate $(III)$ is

$Na_2S + Na_2[Fe(CN)_5NO] \to Na_4[Fe(CN)_5NOS]$; what are the oxidation numbers of $Fe$ in the reactant complex and the product complex,respectively?

What is the oxidation number of $Fe$ in $K_3[Fe(CN)_6]$?

The $IUPAC$ name of the complex $[CrCl_2(H_2O)_4]NO_3$ is

What is the oxidation state of $Cr$ in $[Cr(NH_3)_4Cl_2]^{+}$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module