Identify the hydride which is not correctly m | vedclass

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(D) Hydrides are classified based on their electronic structure: $1$. Saline (ionic) hydrides: Formed by $s$-block elements,e.g.,$(NaH)$. $2$. Electro

Vedclass · Accepted Answer

Electron precise hydride - $(HF)$

Vedclass · Answer

(D) Hydrides are classified based on their electronic structure: $1$. Saline (ionic) hydrides: Formed by $s$-block elements,e.g.,$(NaH)$. $2$. Electron-deficient hydrides: Have fewer electrons than required for bonding,e.g.,$(B_2H_6)$. $3$. Electron-precise hydrides: Have the exact number of electrons for bonding,e.g.,$(CH_4)$. $4$. Electron-rich hydrides: Have lone pairs of electrons,e.g.,$(H_2O, NH_3, HF)$. In option $(D)$,$(HF)$ is an electron-rich hydride because it has lone pairs on the fluorine atom,not an electron-precise hydride. Therefore,$(D)$ is incorrectly matched.

Identify the hydride which is not correctly matched with the example given in brackets?

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