Identify the incorrect relationship.

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Question

(D) The correct relationship for the speed of a particle of mass $m$ and charge $e$ accelerated by a potential difference $V$ is derived from the kine

Vedclass · Accepted Answer

Speed of a particle accelerated by a potential difference $V$ is $v = \frac{2 e V}{m}$

Vedclass · Answer

(D) The correct relationship for the speed of a particle of mass $m$ and charge $e$ accelerated by a potential difference $V$ is derived from the kinetic energy equation:$K.E. = e V$$\frac{1}{2} m v^2 = e V$$v^2 = \frac{2 e V}{m}$$v = \sqrt{\frac{2 e V}{m}}$Comparing this with the expression in option $(d)$,we see that the given formula $v = \frac{2 e V}{m}$ is incorrect. Therefore,option $(d)$ is the incorrect relationship.

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