Identify the incorrect statement related to $PCl_{5}$ from the following:
- AThree equatorial $P-Cl$ bonds make an angle of $120^{\circ}$ with each other.
- BTwo axial $P-Cl$ bonds make an angle of $180^{\circ}$ with each other.
- CAxial $P-Cl$ bonds are longer than equatorial bonds.
- D$PCl_{5}$ molecule is non-reactive.
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Similar Questions
$(a)$ Bond angle in $PH_{4}^{+}$ is higher than that in $PH_{3}$. Why?
$(b)$ What is formed when $PH_{3}$ reacts with an acid?
$(b)$ What is formed when $PH_{3}$ reacts with an acid?
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Explain the non-linear shape of $H_2S$ and the non-planar shape of $PCl_3$ using the Valence Shell Electron Pair Repulsion $(VSEPR)$ theory.
Medium
View SolutionBased on the $VSEPR$ model,match the xenon compounds given in List-$I$ with the corresponding geometries and the number of lone pairs on xenon given in List-$II$ and choose the correct option.
List-$I$ List-$II$ $(P)$ $XeF_2$ $(5)$ Trigonal bipyramidal and three lone pairs of electrons $(Q)$ $XeF_4$ $(3)$ Square planar and two lone pairs of electrons $(R)$ $XeO_3$ $(2)$ Pyramidal and one lone pair of electrons $(S)$ $XeO_3F_2$ $(4)$ Trigonal bipyramidal and no lone pairs of electrons
| List-$I$ | List-$II$ |
|---|---|
| $(P)$ $XeF_2$ | $(5)$ Trigonal bipyramidal and three lone pairs of electrons |
| $(Q)$ $XeF_4$ | $(3)$ Square planar and two lone pairs of electrons |
| $(R)$ $XeO_3$ | $(2)$ Pyramidal and one lone pair of electrons |
| $(S)$ $XeO_3F_2$ | $(4)$ Trigonal bipyramidal and no lone pairs of electrons |
The numbers of lone pair$(s)$ on $Xe$ in $XeF_2$ and $XeF_4$ are,respectively:
MediumKVPY 2013
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