The numbers of lone pair(s) on Xe in XeF_2 an | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The central atom $Xe$ has $8$ valence electrons.In $XeF_2$,$Xe$ forms $2$ covalent bonds with fluorine atoms,leaving $8 - 2 = 6$ electrons,which c

Vedclass · Accepted Answer

$3$ and $2$

Vedclass · Answer

(C) The central atom $Xe$ has $8$ valence electrons.In $XeF_2$,$Xe$ forms $2$ covalent bonds with fluorine atoms,leaving $8 - 2 = 6$ electrons,which corresponds to $3$ lone pairs.In $XeF_4$,$Xe$ forms $4$ covalent bonds with fluorine atoms,leaving $8 - 4 = 4$ electrons,which corresponds to $2$ lone pairs.Therefore,the number of lone pairs on $Xe$ in $XeF_2$ and $XeF_4$ are $3$ and $2$,respectively.

The numbers of lone pair$(s)$ on $Xe$ in $XeF_2$ and $XeF_4$ are,respectively:

Similar Questions

Which of the following shapes is not possible for any possible value of $n$ in the $XeF_n$ molecule?

Discuss the shape of the following molecules using the $VSEPR$ model: $BeCl_2, BCl_3, SiCl_4, AsF_5, H_2S, PH_3$.

Which of the following species are planar?

The structure of ammonia is:

The structure of $XeF_5^-$ is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module