The structure of XeF_5^- is: | vedclass

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(D) The central atom $Xe$ has $8$ valence electrons.For $XeF_5^-$,the number of electron pairs is calculated as: $\frac{1}{2} (8 + 5 + 1) = 7$.Out of

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Pentagonal planar

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(D) The central atom $Xe$ has $8$ valence electrons.For $XeF_5^-$,the number of electron pairs is calculated as: $\frac{1}{2} (8 + 5 + 1) = 7$.Out of these $7$ electron pairs,$5$ are bond pairs and $2$ are lone pairs.According to $VSEPR$ theory,the steric number $7$ corresponds to pentagonal bipyramidal geometry.With $5$ bond pairs and $2$ lone pairs,the lone pairs occupy the axial positions to minimize repulsion,resulting in a pentagonal planar molecular geometry.

The structure of $XeF_5^-$ is:

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