Identify the ionization isomer of [Cr(H_2O)_4 | vedclass

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(B) Step $1$: Ionization isomers are compounds that produce different ions in solution. This occurs when a counter ion in the coordination compound ex

Vedclass · Accepted Answer

$[Cr(H_2O)_4 Cl_2](NO_2)$

Vedclass · Answer

(B) Step $1$: Ionization isomers are compounds that produce different ions in solution. This occurs when a counter ion in the coordination compound exchanges its position with a ligand present in the coordination sphere.Step $2$: The given complex is $[Cr(H_2O)_4 Cl(NO_2)] Cl$. Here, $Cl^-$ is the counter ion.Step $3$: To form an ionization isomer, the $Cl^-$ ion outside the coordination sphere must exchange with a ligand inside the sphere (e.g., $NO_2^-$).Step $4$: Swapping $Cl^-$ with $NO_2^-$ gives the complex $[Cr(H_2O)_4 Cl_2](NO_2)$.Step $5$: Thus, option $B$ is the correct ionization isomer.

List $I$ (Complex)	List $II$ (Type of isomerism)
$A$. $[Pt(NH_3)_2Cl_2]$	$I$. Optical
$B$. $[Co(en)_3]^{3+}$	$II$. Solvate
$C$. $[Co(NH_3)_5NO_2]Cl_2$	$III$. Geometrical
$D$. $[Cr(H_2O)_6]Cl_3$	$IV$. Linkage

Identify the ionization isomer of $[Cr(H_2O)_4 Cl(NO_2)] Cl$ from the following.

Similar Questions

Match List $I$ with List $II$ :
List $I$ (Complex) List $II$ (Type of isomerism)
$A$. $[Pt(NH_3)_2Cl_2]$ $I$. Optical
$B$. $[Co(en)_3]^{3+}$ $II$. Solvate
$C$. $[Co(NH_3)_5NO_2]Cl_2$ $III$. Geometrical
$D$. $[Cr(H_2O)_6]Cl_3$ $IV$. Linkage

Choose the correct answer from the options given below :

Total number of geometrical isomers of $[Ma_3b_3]$ is/are:

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Which of the following is true for $[Fe(CN)_6]^{3-}$ and $[FeF_6]^{3-}$?

$A$ reaction of cobalt $(III)$ chloride and ethylenediamine in a $1:2$ mole ratio generates two isomeric products $A$ (violet coloured) and $B$ (green coloured). $A$ can show optical activity,but $B$ is optically inactive. What type of isomers do $A$ and $B$ represent?

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