Identify the molecule in which the arrangemen | vedclass

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(C) The arrangement of electron pairs around the central atom is octahedral when the steric number is $6$ (i.e.,$sp^3d^2$ hybridization). $A$ molecule

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$BrF_5$

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(C) The arrangement of electron pairs around the central atom is octahedral when the steric number is $6$ (i.e.,$sp^3d^2$ hybridization). $A$ molecule has a non-octahedral shape if it contains one or more lone pairs of electrons.$(i)$ $SF_6$: Steric number = $6$ ($6$ bond pairs,$0$ lone pairs). Shape is octahedral.$(ii)$ $XeF_6$: Steric number = $7$ ($6$ bond pairs,$1$ lone pair). The electron pair arrangement is pentagonal bipyramidal,not octahedral.$(iii)$ $BrF_5$: Steric number = $6$ ($5$ bond pairs,$1$ lone pair). The electron pair arrangement is octahedral,but the shape is square pyramidal (not octahedral).$(iv)$ $XeO_2F_4$: Steric number = $6$ ($6$ bond pairs,$0$ lone pairs). Shape is octahedral.Therefore,$BrF_5$ is the molecule where the electron pair arrangement is octahedral but the shape is not.

Identify the molecule in which the arrangement of electron pairs around the central atom is octahedral and the shape is not octahedral.

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