Identify the position where E.A.S. (Electroph | vedclass

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(A) The molecule is $2$-methylcarbazole. Electrophilic aromatic substitution $(E.A.S.)$ occurs preferentially on the more electron-rich ring. The nitr

Vedclass · Accepted Answer

$1$

Vedclass · Answer

(A) The molecule is $2$-methylcarbazole. Electrophilic aromatic substitution $(E.A.S.)$ occurs preferentially on the more electron-rich ring. The nitrogen atom donates electron density via resonance to both rings. However,the ring on the right has a methyl group $(-CH_3)$,which is an electron-donating group ($+I$ effect and hyperconjugation). Therefore,the right ring is more activated than the left ring. Within the right ring,the positions ortho and para to the nitrogen atom are the most reactive. Position $1$ is ortho to the nitrogen atom and is highly activated. Thus,$E.A.S.$ takes place at position $1$.

Identify the position where $E.A.S.$ (Electrophilic Aromatic Substitution) can take place in the given molecule.

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