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(C) The reaction is an intramolecular aldol condensation of $o$-phthalaldehyde (benzene$-1,2-$dicarbaldehyde). In the presence of a base $(NaOH)$,one

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(C) The reaction is an intramolecular aldol condensation of $o$-phthalaldehyde (benzene$-1,2-$dicarbaldehyde). In the presence of a base $(NaOH)$,one of the aldehyde groups forms an enolate ion,which then attacks the other carbonyl group to form a cyclic structure. This leads to the formation of $1$-hydroxy-indane-$2$-one or,upon dehydration,$1H$-indene-$2$-carbaldehyde. However,looking at the provided options,the structure corresponding to the cyclized product of $o$-phthalaldehyde under these conditions is $1H$-indene-$2$-carbaldehyde (Option $C$).

Identify the principal product of the following reaction:

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