Identify the product formed in the following | vedclass

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(B) The reaction of a Grignard reagent $(RMgX)$ with dry ice $(CO_2)$ followed by acid hydrolysis yields a carboxylic acid with one carbon atom more t

Vedclass · Accepted Answer

Propanoic acid

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(B) The reaction of a Grignard reagent $(RMgX)$ with dry ice $(CO_2)$ followed by acid hydrolysis yields a carboxylic acid with one carbon atom more than the alkyl group of the Grignard reagent.In this reaction,$CH_3CH_2MgBr$ (Ethyl magnesium bromide) reacts with $CO_2$ to form an intermediate complex,$CH_3CH_2COOMgBr$.Upon subsequent hydrolysis with dilute $HCl$,the complex is converted into $CH_3CH_2COOH$,which is Propanoic acid.The overall reaction is: $CH_3CH_2MgBr + CO_2$ $\rightarrow CH_3CH_2COOMgBr$ $\xrightarrow{H_3O^+} CH_3CH_2COOH + Mg(OH)Br$.

Identify the product formed in the following reaction: $CH_3CH_2MgBr$ $\xrightarrow{i. \text{Dry ice} / \text{dry ether}}$ $\xrightarrow{ii. \text{dil. } HCl} \text{Product}$

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$CH_3MgBr + CO_2$ $\xrightarrow{\text{Dry ether}} Y$ $\xrightarrow{H_3O^{\oplus}} Z$
Identify $Z$ from the following.

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